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🎨 Update Exception-Handling for send_user_notification

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洛水居室 2022-11-17 20:36:25 +08:00
parent b323dc0e64
commit 4c10475dca
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1 changed files with 10 additions and 6 deletions
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16
utils/decorators/error.py
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@ -32,16 +32,20 @@ async def send_user_notification(update: Update, context: CallbackContext, text:
chat = update.effective_chat chat = update.effective_chat
if message is None: if message is None:
update_str = update.to_dict() if isinstance(update, Update) else str(update) update_str = update.to_dict() if isinstance(update, Update) else str(update)
logger.warning("错误的消息类型\n" + json.dumps(update_str, indent=2, ensure_ascii=False)) logger.warning("错误的消息类型\n %s", json.dumps(update_str, indent=2, ensure_ascii=False))
return return
logger.info(f"尝试通知用户 {user.full_name}[{user.id}] " f"在 {chat.full_name}[{chat.id}]" f"的 错误信息[{text}]") logger.info("尝试通知用户 %s[%s] 在 %s[%s] 的错误信息[%s]", user.full_name, user.id, chat.full_name, chat.id, text)
try: try:
await message.reply_text(text, reply_markup=buttons, allow_sending_without_reply=True) await message.reply_text(text, reply_markup=buttons, allow_sending_without_reply=True)
except (BadRequest, Forbidden, Exception) as exc: except ConnectTimeout:
logger.error(f"发送 update_id[{update.update_id}] 错误信息失败 错误信息为") logger.error("httpx 模块连接服务器 ConnectTimeout 发送 update_id[%s] 错误信息失败", update.update_id)
except BadRequest as exc:
logger.error("发送 update_id[%s] 错误信息失败 错误信息为 [%s]", update.update_id, exc.message)
except Forbidden as exc:
logger.error("发送 update_id[%s] 错误信息失败 错误信息为 [%s]", update.update_id, exc.message)
except Exception as exc:
logger.error("发送 update_id[%s] 错误信息失败 错误信息为 [%s]", update.update_id, repr(exc))
logger.exception(exc) logger.exception(exc)
finally:
pass
def telegram_warning(update: Update, text: str): def telegram_warning(update: Update, text: str):