# 这个轴的手法会按照一些常见的玩家操作去模拟，主要包括：
# 起手行秋开大同时万叶开大染水风，每个技能之间穿插平 a 触发行秋水剑；
# 班尼特 qe 切香菱 qe 吃球，行秋 eqe 吃球，香菱和行秋的 e 衔接闪避取消后摇；
# 然后在保证香菱站班圈开大的基础上，所有人有 eq 尽快施放。
# 即便如此，仍然推荐堆至少如下的充能，避免因切人打球阶段过长导致模拟结果骤降：
# 香菱：180%，行秋：170%，班尼特：170%

kazuha char lvl=90/90 cons=0 talent=9,9,9;
kazuha add weapon="favoniussword" refine=5 lvl=90/90;
#kazuha add weapon="ironsting" refine=5 lvl=90/90;
kazuha add set="viridescentvenerer" count=5;
kazuha add stats hp=4780 atk=311 em=187 em=187 em=187;
kazuha add stats er=0.44 em=160 cr=0.264 cd=0.132;

xiangling char lvl=90/90 cons=6 talent=9,9,9;
xiangling add weapon="thecatch" refine=5 lvl=90/90;
xiangling add set="emblemofseveredfate" count=5;
xiangling add stats hp=4780 atk=311 atk%=0.466 pyro%=0.466 cr=0.311 ;
xiangling add stats atk%=0.1 er=0.11 em=160 cr=0.198 cd=0.792;

xingqiu char lvl=90/90 cons=6 talent=9,9,9;
#xingqiu add weapon="favoniussword" refine=5 lvl=90/90;
xingqiu add weapon="sacrificialsword" refine=5 lvl=90/90;
xingqiu add set="no" count=5;
xingqiu add stats hp=4780 atk=311 atk%=0.466 hydro%=0.466 cr=0.311;
xingqiu add stats atk%=0.2 er=0.11 em=120 cr=0.231 cd=0.726;

bennett char lvl=90/90 cons=6 talent=9,9,9; 
bennett add weapon="thealleyflash" refine=1 lvl=90/90;
bennett add set="instructor" count=4;
bennett add stats hp=3571 atk=232 er=0.518 hp%=0.466 heal=0.359;
bennett add stats er=0.77 cr=0.264 cd=0.132;

#词条分布
#           atk%  em  er  cr cd
#kazuha      0    8   8   8  2
#xiangling   2    8   2   6  12
#xingqiu     4    6   2   7  11
#bennett     0    0   14  8  2

# 模拟当前充能最差环境, 12-3 水形幻人, 每 33% 血量掉 3 元素微粒, 对于非水系角色等于 1.5 微粒
target lvl=100 resist=0.1 radius=2 pos=0,2.4 hp=3050301 particle_threshold=1016767 particle_drop_count=1.5;
options swap_delay=12 iteration=1000;

fn benn_funnel() {
  if !.bennett.onfield { bennett attack; } # for swap cd
  while .bennett.skill.cd { bennett attack; } 
  bennett skill;
  if .xiangling.energy < .xiangling.energymax {
    if .xiangling.skill.ready { 
      xiangling skill[a4_delay=rand() * 800 - 200], dash, attack:2; # 假设玩家随机捡到辣椒
    } else { 
      xiangling attack: 3; 
    }
  } else if .xingqiu.energy < .xingqiu.energymax {
    xingqiu attack:3;
  } else if .bennett.energy < .bennett.energymax {
    bennett attack:3;
  } 
}

active xingqiu;

while 1 {
  if .xingqiu.burst.ready {
    if !.xingqiu.onfield {
      xingqiu burst, attack:2;
    } else {
      xingqiu burst, attack;
    }
    if .kazuha.burst.ready { kazuha burst, attack; }
  } 
  else if .bennett.burst.ready { 
    bennett attack, burst, attack;
    if .bennett.skill.ready { bennett skill; }
    while .bennett.swap.cd { bennett attack; }
  } else if .xiangling.burst.ready && .status.bennettburst {
    xiangling burst, attack;
    if .xiangling.skill.ready {
      xiangling skill[a4_delay=rand() * 800 - 200], dash, attack; # 假设玩家随机捡到辣椒 
    } 
  } else if .xingqiu.skill.ready {
    if .xingqiu.burst.ready { # 满能量 eqe 操作
      xingqiu skill, dash, burst;
    } else {
      xingqiu skill, dash, attack;
    }
    if .xingqiu.skill.ready { # 意味着触发了祭礼
      xingqiu skill, dash; 
      # 第一次 e 的球已经吃到, 如果充满就开大, 即非满能量 eqe 操作
      if .xingqiu.burst.ready { 
        xingqiu burst, attack:2; 
      } else {
        # 没充满就正常 a 3 下吃球
        xingqiu attack:3;  
      }
    } else { 
      # 没触发祭礼, 正常 a 3 下吃球
      xingqiu attack:3; 
    }
    # 吃完球如果充满也应该开大
    if .xingqiu.burst.ready { xingqiu burst; }
  } else if .kazuha.skill.ready {
    kazuha skill, high_plunge;
    if .xingqiu.status.xingqiuburst { kazuha attack; }
  } else if .kazuha.burst.ready { 
    kazuha burst; 
    if .xingqiu.status.xingqiuburst { kazuha attack; }
  } else if .xiangling.skill.ready {
    xiangling skill, dash, attack:2;
  } else {
    benn_funnel();
  }
}