150 lines
5.9 KiB
C++
150 lines
5.9 KiB
C++
/*
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* Copyright (c) 2019 The WebRTC project authors. All Rights Reserved.
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*
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* Use of this source code is governed by a BSD-style license
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* that can be found in the LICENSE file in the root of the source
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* tree. An additional intellectual property rights grant can be found
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* in the file PATENTS. All contributing project authors may
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* be found in the AUTHORS file in the root of the source tree.
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*/
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#include "modules/audio_coding/neteq/histogram.h"
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#include <algorithm>
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#include <cstdlib>
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#include <numeric>
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#include "absl/types/optional.h"
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#include "rtc_base/checks.h"
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#include "rtc_base/numerics/safe_conversions.h"
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namespace webrtc {
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Histogram::Histogram(size_t num_buckets,
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int forget_factor,
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absl::optional<double> start_forget_weight)
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: buckets_(num_buckets, 0),
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forget_factor_(0),
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base_forget_factor_(forget_factor),
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add_count_(0),
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start_forget_weight_(start_forget_weight) {
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RTC_DCHECK_LT(base_forget_factor_, 1 << 15);
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}
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Histogram::~Histogram() {}
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// Each element in the vector is first multiplied by the forgetting factor
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// `forget_factor_`. Then the vector element indicated by `iat_packets` is then
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// increased (additive) by 1 - `forget_factor_`. This way, the probability of
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// `value` is slightly increased, while the sum of the histogram remains
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// constant (=1).
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// Due to inaccuracies in the fixed-point arithmetic, the histogram may no
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// longer sum up to 1 (in Q30) after the update. To correct this, a correction
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// term is added or subtracted from the first element (or elements) of the
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// vector.
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// The forgetting factor `forget_factor_` is also updated. When the DelayManager
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// is reset, the factor is set to 0 to facilitate rapid convergence in the
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// beginning. With each update of the histogram, the factor is increased towards
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// the steady-state value `base_forget_factor_`.
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void Histogram::Add(int value) {
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RTC_DCHECK(value >= 0);
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RTC_DCHECK(value < static_cast<int>(buckets_.size()));
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int vector_sum = 0; // Sum up the vector elements as they are processed.
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// Multiply each element in `buckets_` with `forget_factor_`.
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for (int& bucket : buckets_) {
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bucket = (static_cast<int64_t>(bucket) * forget_factor_) >> 15;
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vector_sum += bucket;
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}
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// Increase the probability for the currently observed inter-arrival time
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// by 1 - `forget_factor_`. The factor is in Q15, `buckets_` in Q30.
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// Thus, left-shift 15 steps to obtain result in Q30.
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buckets_[value] += (32768 - forget_factor_) << 15;
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vector_sum += (32768 - forget_factor_) << 15; // Add to vector sum.
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// `buckets_` should sum up to 1 (in Q30), but it may not due to
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// fixed-point rounding errors.
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vector_sum -= 1 << 30; // Should be zero. Compensate if not.
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if (vector_sum != 0) {
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// Modify a few values early in `buckets_`.
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int flip_sign = vector_sum > 0 ? -1 : 1;
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for (int& bucket : buckets_) {
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// Add/subtract 1/16 of the element, but not more than `vector_sum`.
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int correction = flip_sign * std::min(std::abs(vector_sum), bucket >> 4);
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bucket += correction;
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vector_sum += correction;
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if (std::abs(vector_sum) == 0) {
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break;
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}
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}
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}
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RTC_DCHECK(vector_sum == 0); // Verify that the above is correct.
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++add_count_;
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// Update `forget_factor_` (changes only during the first seconds after a
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// reset). The factor converges to `base_forget_factor_`.
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if (start_forget_weight_) {
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if (forget_factor_ != base_forget_factor_) {
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int old_forget_factor = forget_factor_;
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int forget_factor =
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(1 << 15) * (1 - start_forget_weight_.value() / (add_count_ + 1));
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forget_factor_ =
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std::max(0, std::min(base_forget_factor_, forget_factor));
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// The histogram is updated recursively by forgetting the old histogram
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// with `forget_factor_` and adding a new sample multiplied by |1 -
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// forget_factor_|. We need to make sure that the effective weight on the
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// new sample is no smaller than those on the old samples, i.e., to
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// satisfy the following DCHECK.
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RTC_DCHECK_GE((1 << 15) - forget_factor_,
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((1 << 15) - old_forget_factor) * forget_factor_ >> 15);
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}
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} else {
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forget_factor_ += (base_forget_factor_ - forget_factor_ + 3) >> 2;
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}
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}
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int Histogram::Quantile(int probability) {
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// Find the bucket for which the probability of observing an
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// inter-arrival time larger than or equal to `index` is larger than or
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// equal to `probability`. The sought probability is estimated using
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// the histogram as the reverse cumulant PDF, i.e., the sum of elements from
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// the end up until `index`. Now, since the sum of all elements is 1
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// (in Q30) by definition, and since the solution is often a low value for
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// `iat_index`, it is more efficient to start with `sum` = 1 and subtract
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// elements from the start of the histogram.
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int inverse_probability = (1 << 30) - probability;
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size_t index = 0; // Start from the beginning of `buckets_`.
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int sum = 1 << 30; // Assign to 1 in Q30.
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sum -= buckets_[index];
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while ((sum > inverse_probability) && (index < buckets_.size() - 1)) {
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// Subtract the probabilities one by one until the sum is no longer greater
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// than `inverse_probability`.
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++index;
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sum -= buckets_[index];
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}
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return static_cast<int>(index);
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}
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// Set the histogram vector to an exponentially decaying distribution
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// buckets_[i] = 0.5^(i+1), i = 0, 1, 2, ...
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// buckets_ is in Q30.
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void Histogram::Reset() {
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// Set temp_prob to (slightly more than) 1 in Q14. This ensures that the sum
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// of buckets_ is 1.
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uint16_t temp_prob = 0x4002; // 16384 + 2 = 100000000000010 binary.
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for (int& bucket : buckets_) {
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temp_prob >>= 1;
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bucket = temp_prob << 16;
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}
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forget_factor_ = 0; // Adapt the histogram faster for the first few packets.
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add_count_ = 0;
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}
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int Histogram::NumBuckets() const {
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return buckets_.size();
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}
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} // namespace webrtc
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