🐛 Fix cannot parse @username
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3
ci.py
3
ci.py
@ -1,7 +1,7 @@
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from configparser import RawConfigParser
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from pyrogram import Client
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from apscheduler.schedulers.asyncio import AsyncIOScheduler
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from httpx import AsyncClient
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from httpx import AsyncClient, get
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# 读取配置文件
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config = RawConfigParser()
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config.read("config.ini")
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@ -15,6 +15,7 @@ headers = {
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"user-agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/76.0.3809.132 Safari/537.36"
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}
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client = AsyncClient(timeout=10.0, headers=headers)
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me = get(f"https://api.telegram.org/bot{bot_token}/getme").json()
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# 初始化客户端
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scheduler = AsyncIOScheduler()
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if not scheduler.running:
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@ -6,6 +6,7 @@ from pyrogram import Client, emoji
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from pyrogram.types import Message, InlineQuery, CallbackQuery
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from pyrogram import filters as Filters
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from ci import me
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from plugins.enemies import enemies_msg
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from plugins.mys2 import mys2_msg, mys2_qun_msg
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from plugins.start import welcome_command, ping_command, help_command, leave_command, help_callback
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@ -118,7 +119,7 @@ async def process_group_msg(client: Client, message: Message):
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text = message.text
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msg_list = text.split(' ')
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# 帮助消息
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if msg_list[0] == '/help':
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if msg_list[0] == '/help' or msg_list[0] == f'/help@{me["result"]["username"]}':
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await help_command(client, message)
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# # 武器查询
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if text.startswith('武器查询') or text.startswith('武器资料'):
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