""" Video + Music Stream Telegram Bot Copyright (c) 2022-present levina=lab This program is free software: you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation, either version 3 of the License, or (at your option) any later version. This program is distributed in the hope that it will be useful, but without any warranty; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for more details. You should have received a copy of the GNU General Public License along with this program. If not, see """ from pyrogram import Client, errors from pyrogram.types import ( InlineQuery, InlineQueryResultArticle, InputTextMessageContent, ) from youtubesearchpython import VideosSearch @Client.on_inline_query() async def inline(client: Client, query: InlineQuery): answers = [] search_query = query.query.lower().strip().rstrip() if search_query == "": await client.answer_inline_query( query.id, results=answers, switch_pm_text="Type the YouTube video name to search !", switch_pm_parameter="help", cache_time=0, ) else: search = VideosSearch(search_query, limit=50) for result in search.result()["result"]: answers.append( InlineQueryResultArticle( title=result["title"], description="{}, {} views.".format( result["duration"], result["viewCount"]["short"] ), input_message_content=InputTextMessageContent( "🔗 https://www.youtube.com/watch?v={}".format(result["id"]) ), thumb_url=result["thumbnails"][0]["url"], ) ) try: await query.answer(results=answers, cache_time=0) except errors.QueryIdInvalid: await query.answer( results=answers, cache_time=0, switch_pm_text="error: search timed out", switch_pm_parameter="", )