79 lines
1.5 KiB
C
79 lines
1.5 KiB
C
#include<stdio.h>
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#include<stdlib.h>
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#include<conio.h>
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#define MAX 100
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void Search1(int a[], int n, int key){
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int i=0;
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a[n] = key;
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while(a[i] != key){
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i++;
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}
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if(i == n){
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printf("\n未找到。\n\n");
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} else {
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printf("\n此数在第 %d 位。\n\n", i + 1);
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}
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}
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void Search2(int a[], int n, int key){
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int low = 0, high = n-1, mid;
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while(low <= high){
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mid = (low + high) / 2;
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if(a[mid] == key){
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printf("\n此数在第 %d 位。\n\n", mid + 1);
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return;
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} else if (a[mid] > key){
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high = mid - 1;
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} else {
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low = mid + 1;
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}
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}
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printf("\n未找到。\n\n");
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}
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int main(){
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int n, choice, e, a[MAX];
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for(;;){
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printf("\t\t1.无序线性表的顺序查找\n");
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printf("\t\t2.有序线性表的二分查找\n");
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printf("\t\t0.退出\n");
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printf("请选择：");
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scanf("%d",&choice);
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if(choice==0) break;
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switch (choice) {
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case 1:
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printf("请输入需要输入的元素个数：");
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scanf("%d",&n);
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for(int i=0;i<n;i++){
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printf("请输入第 %d 个元素：",i+1);
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scanf("%d",&e);
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a[i] = e;
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}
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printf("\n请输入需要查找的元素：");
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scanf("%d",&e);
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Search1(a, n, e);
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break;
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case 2:
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printf("请输入需要输入的元素个数：");
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scanf("%d",&n);
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for(int i=0;i<n;i++){
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printf("请输入第 %d 个元素：",i+1);
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scanf("%d",&e);
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a[i] = e;
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}
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printf("\n请输入需要查找的元素：");
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scanf("%d",&e);
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Search1(a, n, e);
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break;
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default:
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break;
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}
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printf("请按任意键继续...");
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getch();
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system("cls");
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}
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printf("感谢使用，再见\n");
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return 0;
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}
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