From 48e7778b8263c6526cdde39804cc00227e778c50 Mon Sep 17 00:00:00 2001 From: xtaodada Date: Mon, 25 Oct 2021 13:26:59 +0800 Subject: [PATCH] =?UTF-8?q?=E5=AE=9E=E9=AA=8C=E4=B8=89=20=E9=80=89?= =?UTF-8?q?=E6=8B=A9=E7=BB=93=E6=9E=84=E5=9F=BA=E7=A1=80=EF=BC=882?= =?UTF-8?q?=E5=AD=A6=E6=97=B6=EF=BC=89?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- .gitignore | 1 + 03/1/1.c | 20 +++++++++++++++++++ 03/1/1.png | Bin 0 -> 12650 bytes 03/1/README.md | 44 +++++++++++++++++++++++++++++++++++++++++ 03/2/2.c | 26 +++++++++++++++++++++++++ 03/2/README.md | 31 +++++++++++++++++++++++++++++ 03/3/3.c | 52 +++++++++++++++++++++++++++++++++++++++++++++++++ 03/3/README.md | 44 +++++++++++++++++++++++++++++++++++++++++ 03/README.md | 25 ++++++++++++++++++++++++ README.md | 4 ++++ 10 files changed, 247 insertions(+) create mode 100644 03/1/1.c create mode 100644 03/1/1.png create mode 100644 03/1/README.md create mode 100644 03/2/2.c create mode 100644 03/2/README.md create mode 100644 03/3/3.c create mode 100644 03/3/README.md create mode 100644 03/README.md diff --git a/.gitignore b/.gitignore index c6127b3..02c7caa 100644 --- a/.gitignore +++ b/.gitignore @@ -50,3 +50,4 @@ modules.order Module.symvers Mkfile.old dkms.conf +.idea/ diff --git a/03/1/1.c b/03/1/1.c new file mode 100644 index 0000000..f16cb24 --- /dev/null +++ b/03/1/1.c @@ -0,0 +1,20 @@ +#include + +int sign(int x){ + if (x < 0) + return -1; + else + if (x > 0) + return 1; + else + return x; +} + +int main(){ + + int x; + + printf("Enter x: "); + scanf("%d", &x); + printf("\nsign(%d)=%d",x,sign(x)); +} diff --git a/03/1/1.png b/03/1/1.png new file mode 100644 index 0000000000000000000000000000000000000000..39b139c2034043ffd9f6a5792f4a6f5493dc766f GIT binary patch literal 12650 zcmV-wF_q4VP)>fB9@qlC7KYsCW;Yb5)~;@6(v?cLTnT%qNpHtqhc(Hl86vd zK%}npy1>#|V3+Oft<%rU-2Zhy=bhbU-Cf?rg88qVy=G_LDQ8Z(&(qFxp3?>gV+#Rf 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z-;I!C+kPCrZ%GWrKym&xWjGs(*8&TM8HdL;oMj>Sur{)6+A@Vgn+)#BwXrk6At4ls z$S4q8be`)cQUp*YY&!u@S#Xpq&JdOgVHn!p=s9UTJZc2;wr+!ykr^qhv;r|3lx6Wu zBp(uN+(`i$A7|C7RT3@iqmMok8PcZbjhm3s2^zO8lj}h#PXSAli8Mt4YO1+GXy(L#r*<9$ZIr6HUS z5L`T*;3FH2K*(y5$P=8i95Of)XAzPr@;w(RBMn#iNLf1i7(y4zmgQjL#3zOIlkyXU zOs^G)S%55?M z1r31mqHi%Ulq1xRYiX}uy%Mke{bf{E7VA*QnHhevu)Fvq5_|+9ZH8RaSsUd8rNbmM z|6)swqC!NKA>>e#MTR?8TqvAj?Ccb5C#^#q2R>4!EuoJY(r)>(Md;bHo1SXQsJ9G- z*9yd_Mn9ipoeWr~J@Xp3`uAjbkM=wPr1qMTdC1hdGvP>R&#QA!%`Sfgz25ZqNoNQQ z?lrLrSe9OXLZ+J5hAv?TA@!zbjfMpC%Cv;i326071DX$O;59r~v=NDtlNr9uq$lxp zIO3EkTXl80Fn0PcQW?_a)GWT0B4*dlpW{;mCqa`jUe_ag^@vRN)KH#`=t@1H$aMmP zIxdeI^!pa1US9TLxb@O$n5pJ|N9D>K8$Mc>7wvdf|9&eF_idT~!e4AoO^F11QR~VN zf-nQb+UwaBvG(!kq~Wn1RV!Z literal 0 HcmV?d00001 diff --git a/03/1/README.md b/03/1/README.md new file mode 100644 index 0000000..73bf7d3 --- /dev/null +++ b/03/1/README.md @@ -0,0 +1,44 @@ +【问题描述】 输入x,计算并输出下列分段函数sign(x)的值｡要求定义和调用函数sign(x) 实现该分段函数｡ + +![1](1.png) + +【输入形式】从键盘输入整数x +【输入输出样例1】（下划线部分表示输入） + +Enter x: 10 + +sign(10)=1 + +【输入输出样例2】（下划线部分表示输入） + +Enter x: -5 + +sign(-5)=-1 + +【输入输出样例3】（下划线部分表示输入） + +Enter x: 0 + +sign(0)=0 + +【样例说明】 + +输入提示符后要加一个空格。例如Enter x:，其中:后要加一个且只能一个空格。 + +输出语句的=两边无空格。 + +英文字母区分大小写。必须严格按样例输入输出。 + +# 运行结果 + +成功通过编译, 且无编译警告 + +共有测试数据:3 +平均占用内存:1.943K +平均CPU时间:0.00549S +平均墙钟时间:0.00548S + +测试数据 评判结果 +测试数据1 完全正确 +测试数据2 完全正确 +测试数据3 完全正确 diff --git a/03/2/2.c b/03/2/2.c new file mode 100644 index 0000000..5f0c990 --- /dev/null +++ b/03/2/2.c @@ -0,0 +1,26 @@ +#include + +int main() +{ + float a,b; + char c; + scanf("%f %c %f",&a,&c,&b); + switch (c) { + case '+': + printf("=%.2f",a+b); + break; + case '-': + printf("=%.2f",a-b); + break; + case '*': + printf("=%.2f",a*b); + break; + case '/': + printf("=%.2f",a/b); + break; + default: + printf("无效运算符"); + break; + } + return 0; +} diff --git a/03/2/README.md b/03/2/README.md new file mode 100644 index 0000000..60d0437 --- /dev/null +++ b/03/2/README.md @@ -0,0 +1,31 @@ +【问题描述】 编程题：输入一个形式如“操作数 运算符 操作数”的四则运算表达式，输出运算结果。 + +【输入形式】 “操作数 运算符 操作数”，三者之间没有任何符号，操作数可以是整数或小数，运算符为“+ - * /”共4种情况，若为其他运算符，则不计算，直接输出“无效运算符” + +【输出形式】 有效运算符，输出“=结果”，结果保留2位小数；其他运算符直接输出“无效运算符” + +【样例输入1】3.5+4.5 + +【样例输出1】=8.00 + +【样例输入2】5/3 + +【样例输出2】=1.67 + +【样例输入3】3^4 + +【样例输出3】无效运算符 + +# 运行结果 + +成功通过编译, 且无编译警告 + +共有测试数据:3 +平均占用内存:1.982K +平均CPU时间:0.00460S +平均墙钟时间:0.00459S + +测试数据 评判结果 +测试数据1 完全正确 +测试数据2 完全正确 +测试数据3 完全正确 diff --git a/03/3/3.c b/03/3/3.c new file mode 100644 index 0000000..acae059 --- /dev/null +++ b/03/3/3.c @@ -0,0 +1,52 @@ +#include + +int number(int num){ + + int a = num % 3,b = num % 5,c = num % 7; + + if (a == 0) { + if (b == 0) { + if (c == 0) { + printf("Can be divisible by 3,5,7."); + } + else { + printf("Can be divisible by 3,5."); + } + } + else { + if (c == 0) { + printf("Can be divisible by 3,7."); + } + else { + printf("Can be divisible by 3."); + } + } + } + else { + if (b == 0) { + if (c == 0) { + printf("Can be divisible by 5,7."); + } + else { + printf("Can be divisible by 5."); + } + } + else { + if (c == 0) { + printf("Can be divisible by 7."); + } + else { + printf("Can not be divisible by 3,5,7."); + } + } + } + return 0; +} + +int main() +{ + int num; + scanf("%d",&num); + number(num); + return 0; +} diff --git a/03/3/README.md b/03/3/README.md new file mode 100644 index 0000000..826c492 --- /dev/null +++ b/03/3/README.md @@ -0,0 +1,44 @@ +【问题描述】 编程，从键盘输入一个整数，判断它能否被3,5,7整除，并输出以下信息之一： + +⑴ Can be divisible by 3,5,7. + + 即能同时被3,5,7整除； + +⑵ Can be divisible by ?,?. (其中?为3,5,7之一) + + 即能被其中两个数(要指出哪两个)整除； + +⑶ Can be divisible by ?. (其中?为3,5,7之一) + + 即能被其中一个数(要指出哪一个)整除； + +⑷ Can not be divisible by 3,5,7. + + 即不能被3,5,7任一个整除。 + +【输入形式】 从键盘输入一个整数。 + +【输出形式】 按题目要求及样例，输出该整数能否被3,5,7整除。 + +【样例输入1】 441 + +【样例输出1】 Can be divisible by 3,7. + +【样例输入2】 1024 + +【样例输出2】 Can not be divisible by 3,5,7. + +# 运行结果 + +成功通过编译, 且无编译警告 + +共有测试数据:4 +平均占用内存:1.935K +平均CPU时间:0.00395S +平均墙钟时间:0.00394S + +测试数据 评判结果 +测试数据1 完全正确 +测试数据2 完全正确 +测试数据3 完全正确 +测试数据4 完全正确 diff --git a/03/README.md b/03/README.md new file mode 100644 index 0000000..479f62b --- /dev/null +++ b/03/README.md @@ -0,0 +1,25 @@ +# 实验三 选择结构基础（2学时） + +> 作业时间： 2021-10-24 22:32:00 至 2021-10-31 23:55:00 + +# 实验目的 + +1. 学会正确使用逻辑运算符和逻辑表达式。 +2. 了解条件与程序流程的关系。 +3. 熟练掌握if语句和switch语句。 + +# 实验器材 + +计算机硬件环境：`PIII 667以上计算机；软件环境：Dev C++, Visual C++。` + +# 技能要点 + +1. if语句三种形式的使用； +2. switch语句的格式以及控制流程； +3. 在switch中break语句的作用； +4. 缩进格式程序的编写。 + +# 思考题 + +1. 分支结构中，决定分支的条件一般是什么表达式？ +2. 在C语言中如何判断逻辑真、假，又如何表示逻辑真、假？ diff --git a/README.md b/README.md index eb8c73a..515b376 100644 --- a/README.md +++ b/README.md @@ -24,3 +24,7 @@ A repo to record my study life. - [4. 时间换算](https://github.com/xtaodada/C-study/tree/master/02-1/4) - [5. 求复数之积](https://github.com/xtaodada/C-study/tree/master/02-1/5) - [6. 计算时间差](https://github.com/xtaodada/C-study/tree/master/02-1/6) +- [实验三 选择结构基础（2学时）](https://github.com/xtaodada/C-study/tree/master/03) + - [1. 求分段函数的值](https://github.com/xtaodada/C-study/tree/master/03/1) + - [2. 求解四则运算表达式](https://github.com/xtaodada/C-study/tree/master/03/2) + - [3. 能否被3,5,7整除](https://github.com/xtaodada/C-study/tree/master/03/3)