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优化代码：能否被3,5,7整除

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xtaodada 2021-10-25 13:54:26 +08:00
parent 48e7778b82
commit 717cf8dccf
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GPG Key ID: EE4DC37B55E24736
1 changed files with 25 additions and 33 deletions
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58
03/3/3.c
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@ -2,44 +2,36 @@
int number(int num){
int a = num % 3,b = num % 5,c = num % 7;
int a = num % 3,b = num % 5,c = num % 7,first = 1;
if (a == 0) {
if (b == 0) {
if (c == 0) {
printf("Can be divisible by 3,5,7.");
if (a == 0 || b == 0 || c == 0) {
printf("Can be divisible by ");
if (a == 0)
first = 0;
printf("3");
if (b == 0)
if (first) {
printf("5");
first = 0;
}
else
printf(",5");
// 防止编译器编译时输出警告
else a=a;
if (c == 0)
if (first) {
printf("7");
first = 0;
}
else {
printf("Can be divisible by 3,5.");
}
}
else {
if (c == 0) {
printf("Can be divisible by 3,7.");
}
else {
printf("Can be divisible by 3.");
}
}
else
printf(",7");
// 防止编译器编译时输出警告
else a=a;
}
else {
if (b == 0) {
if (c == 0) {
printf("Can be divisible by 5,7.");
}
else {
printf("Can be divisible by 5.");
}
}
else {
if (c == 0) {
printf("Can be divisible by 7.");
}
else {
printf("Can not be divisible by 3,5,7.");
}
}
printf("Can not be divisible by 3,5,7");
}
printf(".");
return 0;
}