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ex7_1.c

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+#include<stdio.h>
+#include<stdlib.h>
+#include<conio.h>
+#define MAX 100
+
+void Search1(int a[], int n, int key){
+	int i=0;
+	a[n] = key;
+	while(a[i] != key){
+		i++;
+	}
+	if(i == n){
+		printf("\n未找到。\n\n");
+	} else {
+		printf("\n此数在第 %d 位。\n\n", i + 1);
+	}
+}
+void Search2(int a[], int n, int key){
+	int low = 0, high = n-1, mid;
+	while(low <= high){
+		mid = (low + high) / 2;
+		if(a[mid] == key){
+			printf("\n此数在第 %d 位。\n\n", mid + 1);
+			return;
+		} else if (a[mid] > key){
+			high = mid - 1;
+		} else {
+			low = mid + 1;
+		}
+	}
+	printf("\n未找到。\n\n");
+}
+int main(){
+	int n, choice, e, a[MAX];
+
+	for(;;){
+		printf("\t\t1.无序线性表的顺序查找\n");
+		printf("\t\t2.有序线性表的二分查找\n");
+		printf("\t\t0.退出\n");
+
+		printf("请选择：");
+		scanf("%d",&choice);
+		if(choice==0) break;
+		switch (choice) {
+		case 1:
+			printf("请输入需要输入的元素个数：");
+			scanf("%d",&n);
+			for(int i=0;i<n;i++){
+				printf("请输入第 %d 个元素：",i+1);
+				scanf("%d",&e);
+				a[i] = e;
+			}
+			printf("\n请输入需要查找的元素：");
+			scanf("%d",&e);
+			Search1(a, n, e);
+			break;
+		case 2:
+			printf("请输入需要输入的元素个数：");
+			scanf("%d",&n);
+			for(int i=0;i<n;i++){
+				printf("请输入第 %d 个元素：",i+1);
+				scanf("%d",&e);
+				a[i] = e;
+			}
+			printf("\n请输入需要查找的元素：");
+			scanf("%d",&e);
+			Search1(a, n, e);
+			break;
+		default:
+			break;
+		}
+		printf("请按任意键继续...");
+		getch();
+		system("cls");
+	}
+    printf("感谢使用，再见\n");
+	return 0;
+}